Plotting the diagram of given data we get,

Given equation of hyperbola is 9x2−4y2=1.
⇒a2=9,b2=4
We know that, b2=a2(e2−1)
⇒e2=1+a2b2
⇒e2=1+94
⇒e2=913
⇒e=313
Now, S1S2=2ae
⇒S1S2=2×3×313
⇒S1S2=213
It is given that, area of ΔPS1S2 is 213.
⇒21×β×S1S2=213
⇒21×β×213=213
⇒β=2
Since, (α,β) lies on the hyperbola,
⇒9α2−4β2=1
⇒9α2−1=1
⇒α2=18
⇒α=32
Distance of P from origin is given by,
OP=α2+β2
⇒OP=18+4
⇒OP=22
⇒OP2=22