f(x)=x2+9g(x)=x−9xa=f(g(10))=f(10−910)=f(10)=109b=g(f(3))=g(9+9)=g(18)=918=2E:109x2+2y2=1 e2=1−1092=109107ℓ=1092(2)=10948e2+ℓ2=1098(107)+10916=8
Let f(x)=x2+9,g(x)=x−9x and a=f∘g(10),b=g∘f(3). If e and l denote the eccentricity and the length of the latus rectum of the ellipse ax2+by2=1, then 8e2+l2 is equal to.
Held on 9 Apr 2024 · Verified 6 Jul 2026.
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