
21h−12k13111=10−2x+3y=25−56x+59y=15a=−56, b=595a=−6,2 b=518
Let A(−1,1) and B(2,3) be two points and P be a variable point above the line AB such that the area of △PAB is 10 . If the locus of P is ax+by=15, then 5a+2 b is :
Held on 5 Apr 2024 · Verified 6 Jul 2026.
6
−56
4
−512
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