Given,
Ellipse E:x2+9y2=9........(i)
Now point A(3,0)&B(0,1) which is the intersection of given ellipse with positive axis,
So, equation of line passing through A&B is given by,
L:3x+1y=1⇒x=3−3y.......(ii)
Now equation of Circle with diametric point (-3,0)&(3,0) is given by,
C:x2+y2=9........(iii)
Let Q be foot of perpendicular from P upon major axis,
So, from (\mathrm{ii})&(\mathrm{iii}) we get,
(3−3y)2+y2=9
⇒y=59,0
Hence, PQ=59
Now Area of triangle will be,
=21×OA×PQ=21×3×59=1027
Hence, m−n=17