$a^2 = 9$, $b^2 = 16$, $c^2 = a^2 + b^2 = 25$, $c = 5$
Distance between foci $= 2c = 10$
Back to JEE Main 2023 Coordinate Geometry
JEE Main 2023 — Mathematics Coordinate Geometry
medium
mcq
2023
Official previous-year question
Verified 30 May 2026.
Question
The distance between the foci of the hyperbola $\frac{x^2}{9} - \frac{y^2}{16} = 1$ is:
Options
- A
$10$
- B
$8$
- C
$6$
- D
$12$
Solution
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