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Let the hyperbola H: x^2 a^2-y^2=1 and the ellipse E:3x^2+4y^2=12 be such that the length of latus rectum of H is equal to the length of latus rectum…

JEE Main 2022 — Mathematics Coordinate Geometry

2022integermedium

Let the hyperbola H:x2a2−y2=1H:\frac{{x}^{2}}{{a}^{2}}-{y}^{2}=1H:a2x2​−y2=1 and the ellipse E:3x2+4y2=12E:3{x}^{2}+4{y}^{2}=12E:3x2+4y2=12 be such that the length of latus rectum of HHH is equal to the length of latus rectum of EEE. If eH{e}_{H}eH​ and eE{e}_{E}eE​ are the eccentricities of HHH and EEE respectively, then the value of 12(eH2+eE2)12({e}_{H}^{2}+{e}_{E}^{2})12(eH2​+eE2​) is equal to _____.

Official previous-year question

Held on 24 Jun 2022 · Verified 6 Jul 2026.

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