Given C1(5,5),r1=3 and C2(12,5),r2=3
C1C2=7
Now, C1C2>r1+r2
Thus, (P1P2)min=7−6=1

The minimum distance between any two points P1 and P2 while considering point P1 on one circle and point P2 on the other circle for the given circles' equations
x2+y2−10x−10y+41=0
x2+y2−24x−10y+160=0 is ________
Held on 17 Mar 2021 · Verified 6 Jul 2026.
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Let ABC be an equilateral triangle with orthocenter at the origin and the side BC on the line $x+2 \sqrt{2} y=4$. If the co-ordinates of the vertex A are $(\alpha, \beta)$, then the greatest integer less than or equal to $|\alpha+\sqrt{2} \beta|$ is
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Work through every JEE Main Coordinate Geometry PYQ, year by year.