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Let P be a variable point on the parabola y=4x^2+1. Then, the locus of the mid-point of the point P and the foot of the perpendicular drawn from the…

JEE Main 2021 — Mathematics Coordinate Geometry

2021mcqhard

Let PPP be a variable point on the parabola y=4x2+1.y=4{x}^{2}+1.y=4x2+1. Then, the locus of the mid-point of the point PPP and the foot of the perpendicular drawn from the point PPP to the line y=xy=xy=x is:

Official previous-year question

Held on 20 Jul 2021 · Verified 6 Jul 2026.

Options

  1. A

    (3x−y)2+(x−3y)+2=0(3x-y{)}^{2}+(x-3y)+2=0(3x−y)2+(x−3y)+2=0

  2. B

    2(3x−y)2+(x−3y)+2=02(3x-y{)}^{2}+(x-3y)+2=02(3x−y)2+(x−3y)+2=0

  3. C

    (3x−y)2+2(x−3y)+2=0(3x-y{)}^{2}+2(x-3y)+2=0(3x−y)2+2(x−3y)+2=0

  4. D

    2(x−3y)2+(3x−y)+2=02(x-3y{)}^{2}+(3x-y)+2=02(x−3y)2+(3x−y)+2=0

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