Skip to main content

Let an ellipse E: x^2 a^2+ y^2 b^2=1,a^2>b^2, passes through (√ 3 2,1) and has eccentricity 1 √3. If a circle, centered at focus F(α ,0),α >0, of E…

JEE Main 2021 — Mathematics Coordinate Geometry

2021mcqmedium

Let an ellipse E:x2a2+y2b2=1,a2>b2E:\frac{{x}^{2}}{{a}^{2}}+\frac{{y}^{2}}{{b}^{2}}=1,{a}^{2}>{b}^{2}E:a2x2​+b2y2​=1,a2>b2, passes through (32,1)(\sqrt{\frac{3}{2}},1)(23​​,1) and has eccentricity 13\frac{1}{\sqrt{3}}3​1​. If a circle, centered at focus F(α,0),α>0F(\alpha ,0),\alpha >0F(α,0),α>0, of EEE and radius 23\frac{2}{\sqrt{3}}3​2​, intersects EEE at two points PPP and QQQ, then PQ2P{Q}^{2}PQ2 is equal to :

Official previous-year question

Held on 25 Jul 2021 · Verified 6 Jul 2026.

Options

  1. A

    83\frac{8}{3}38​

  2. B

    43\frac{4}{3}34​

  3. C

    163\frac{16}{3}316​

  4. D

    333

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

JEE Main Coordinate Geometry in other years

More JEE Main Coordinate Geometry questions

Other Mathematics topics for JEE Main

Keep practicing Coordinate Geometry

Work through every JEE Main Coordinate Geometry PYQ, year by year.

Browse all Mathematics topics