The ellipse a2x2+b2y2=1 passes through the point (23,1)
So, 2a23+b21=1...(1) and 1−a2b2=31...(2)
On solving equations (1) and (2), we get
\Rightarrow {a}^{2}=3&{b}^{2}=2
⇒3x2+2y2=1...(3)
We know that, focii of the ellipse a2x2+b2y2=1 is (±ae,0)
Here, a=\sqrt{3}&e=\frac{1}{\sqrt{3}}
∴ Its focus is (1,0)(∵α>0)
Now, equation of circle is
(x−1)2+y2=34...(4)
Solving (3) and (4) we get
y=±32,x=1
⇒PQ2=(1−1)2+(32+32)2
=(34)2=316