$(x-1)^2 + (y+2)^2 = 9$
$$x^2 - 2x + 1 + y^2 + 4y + 4 = 9$$
$$x^2 + y^2 - 2x + 4y - 4 = 0$$
Back to JEE Main 2021 Coordinate Geometry
JEE Main 2021 — Mathematics Coordinate Geometry
easy
mcq
2021
Official previous-year question
Verified 30 May 2026.
Question
The equation of the circle with centre $(1, -2)$ and radius $3$ is:
Options
- A
$x^2 + y^2 - 2x + 4y - 4 = 0$
- B
$x^2 + y^2 - 2x + 4y + 4 = 0$
- C
$x^2 + y^2 + 2x - 4y - 4 = 0$
- D
$x^2 + y^2 - 2x - 4y - 4 = 0$
Solution
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