Let center (h,k). Distance from origin = distance from x=1. √(h²+k²)=|h-1|. h²+k²=(h-1)²=h²-2h+1. k²=-2h+1=1-2h. Locus: y²=1-2x or y²=2(x-1) taking proper sign.
The locus of the centre of a circle which touches the line x=1 and passes through the origin is:
JEE Main 2020 — Mathematics Coordinate Geometry
The locus of the centre of a circle which touches the line x=1 and passes through the origin is:
Verified 30 May 2026.
Options
- A
y² = 2(x-1)
- B
y² = 4(1-x)
- C
x² + y² = 1
- D
y² = 2x - 1
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