Since, in parallelogram mid points of both diagonals coinsides. ∴ mid-point of AD= mid-point of BC 
(2x1+1,2y1+2)=(23+2,24+5) ∴(x1,y1)=(4,7) Then, equation of AD is, y−7=1−42−7(x−4) y−7=35(x−4) 3y−21=5x−20 5x−3y+1=0
If in a parallelogram ABDC, the coordinates of A,B and C are respectively (1,2),(3,4) and (2,5), then the equation of the diagonal AD is :
Held on 11 Jan 2019 · Verified 6 Jul 2026.
5x−3y+1=0
5x+3y−11=0
3x−5y+7=0
3x+5y−13=0
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