
Let the equation of line be ax+by=1.......(1)
Clearly P(a,0) and Q(0,b). Also h=a,k=b
Now (1) passes through (2,3)
⇒a2+b3=1
⇒h2+k3=1
Hence, locus is 3x+2y=xy
A straight line through a fixed point (2,3) intersects the coordinate axes at distinct points P and Q. If O is the origin and the rectangle OPRQ is completed, then the locus of R is:
Held on 8 Apr 2018 · Verified 6 Jul 2026.
3x+2y=6xy
3x+2y=6
2x+3y=xy
3x+2y=xy
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