
To find point of intersection of given chord y=−3x with the given circle x2+y2−30x=0 eliminate y from two equations
Point of intersection
⇒ x2+9x2−30x=0
⇒ 10x(x−3)=0
⇒ x=0 or x=3
Therefore, y=0 and y=−9 are the corresponding ordinates.
Point of intersection (0,0), (3,−9)
Diametric form of equation of circle,
x(x−3)+y(y+9)=0
⇒x2+y2−3x+9y=0 .