The centre of the given ellipse (0,0)
The general equation of a tangent to the ellipse
a2x2+b2y2=1 is y=mx±a2m2+b2...(1)
Given ellipse : 6x2+2y2=1
A perpendicular line from the centre is y=−mx...(2)
Eliminating m, from (1) and (2)
y=(y−x)x±a2(y2x2)+b2
y2=−x2±ya2(y2x2)+b2
∴x2+y2=±a2x2+b2y2
Squaring both sides,
(x2+y2)2=a2x2+b2y2=6x2+2y2