P(2,2);Q(6,−1);R(7,3)
S is the midpoint of Q and R.
∴S≡(213,1)
∴Slope of PS=2−2132−1=(2−9)1=9−2
Therefore, the equation of the line passing through (1,−1) and parallel toPS is
y+1=9−2(x−1)
∴9y+9=−2x+2
∴2x+9y+7=0
JEE Main 2014 — Mathematics Coordinate Geometry
Let PS be the median of the triangle with vertices P(2,2),Q(6,−1) and R(7,3). The equation of the line passing through (1,−1)and parallel to PS is
Held on 6 Apr 2014 · Verified 6 Jul 2026.
4x+7y+3=0
2x−9y−11=0
4x−7y−11=0
2x+9y+7=0
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