Let, x2+y2=16 or x2+y2=42 radius of circle r1=4, centre C1(0,0) we have, x2+y2−2y=0 ⇒=x2+(y2−2y+1)−1=0 or x2+(y−1)212 Radius 1, centre C2(0,1) ∣C1C2∣=1∣r2−r1∣=∣4−1∣=3∣C1C2∣<∣r2−r1∣ no common tangents for these two circles.
JEE Main 2014 — Mathematics Coordinate Geometry
For the two circles x2+y2=16 and x2+y2−2y=0, there is/are
Held on 12 Apr 2014 · Verified 6 Jul 2026.
one pair of common tangents
two pair of common tangents
three pair of common tangents
no common tangent
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