
Let (x1,y1),(x2,y2) and (x3,y3) be the vertices of a triangle,
So,
x1+x2=0,x2+x3=2,x3+x1=2 [mid point formula 2x1+x2 ]
Similarly,
y1+y2=2,y2+y3=2,y3+y1=0
So, the vertices are (0,0),(0,2),(2,0).
We know that x-coordinate of incentre xˉ=a+b+cax1+bx2+cx3
a=2,b=2,c=22,x1=0,x2=2,x3=0
∴xˉ=2+2+220+4+0
⇒xˉ=(2−2)