Given equations of ellipses E1:3x2+2y2=1⇒e1=1−32=31 and E2:16x2+b2y2=1⇒e2=161−b2=416−b2 Also, given e1×e2=21⇒31×416−b2=21⇒16−b2=12⇒b2=4∴ Length of minor axis of E2=2b=2×2=4
Let the equations of two ellipses be E_1: x^2 3+ y^2 2=1 and E_2: x^2 16+ y^2 b^2=1 , If the product of their eccentricities is 1 2, then the length…
JEE Main 2013 — Mathematics Coordinate Geometry
Let the equations of two ellipses be E1:3x2+2y2=1 and E2:16x2+b2y2=1, If the product of their eccentricities is 21, then the length of the minor axis of ellipse E2 is :
Held on 22 Apr 2013 · Verified 6 Jul 2026.
Options
- A
8
- B
9
- C
4
- D
2
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