x2+4y2=4⇒4x2+1y2=1⇒a=2,b=1⇒P=(2,1) Required Ellipse is a2x2+b2y2=1⇒42x2+b2y2=1 (2,1) lies on it ⇒164+b21=1⇒b21=1−41=43⇒b2=34∴16x2+(34)y2=1⇒16x2+43y2=1⇒x2+12y2=16 
The ellipse x^2+4 y^2=4 is inscribed in a rectangle aligned with the coordinate axes, which in turn in inscribed in another ellipse that passes…
JEE Main 2009 — Mathematics Coordinate Geometry
The ellipse x2+4y2=4 is inscribed in a rectangle aligned with the coordinate axes, which in turn in inscribed in another ellipse that passes through the point (4,0). Then the equation of the ellipse is
Held on 30 Apr 2009 · Verified 6 Jul 2026.
Options
- A
x2+16y2=16
- B
x2+12y2=16
- C
4x2+48y2=48
- D
4x2+64y2=48
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