F = qv×B acts as centripetal force → circular path.
Back to JEE Advanced 2026 Electromagnetism
JEE Advanced 2026 — Physics Electromagnetism
easy
mcq
2026
Official previous-year question
Verified 30 May 2026.
Question
A charged particle enters a uniform magnetic field perpendicular to its velocity. The path of the particle is:
Options
- A
Straight line
- B
Circular
- C
Elliptical
- D
Parabolic
Solution
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