Back to JEE Advanced 2026 Electromagnetism

JEE Advanced 2026Physics Electromagnetism

medium
mcq
2026
Official previous-year question

Verified 30 May 2026.

Question

A circular loop of radius $R$ carries current $I$. The magnetic field at a point on the axis at distance $x$ from the center is:

Options

  1. A

    $\frac{\mu_0 I R^2}{2(R^2 + x^2)^{3/2}}$

  2. B

    $\frac{\mu_0 I}{2R}$

  3. C

    $\frac{\mu_0 I R}{2(R^2 + x^2)}$

  4. D

    $\frac{\mu_0 I x^2}{2R^3}$

Solution

Using the Biot-Savart law, the axial magnetic field of a circular loop:

$$B = \frac{\mu_0 I R^2}{2(R^2 + x^2)^{3/2}}$$

At the center ($x = 0$): $B = \frac{\mu_0 I}{2R}$

At large distance ($x \gg R$): $B \approx \frac{\mu_0 I R^2}{2x^3} = \frac{\mu_0 m}{4\pi x^3}$ (dipole field)

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

JEE Advanced Electromagnetism in other years

More JEE Advanced Electromagnetism Questions

Other Physics Topics for JEE Advanced