Back to JEE Advanced 2025 Calculus

JEE Advanced 2025 — Mathematics Calculus

medium
mcq
2025
Official previous-year question

Verified 30 May 2026.

Question

The area enclosed between the curves y = x² and y = x is:

Options

  1. A

    1/6

  2. B

    1/3

  3. C

    1/2

  4. D

    1/4

Solution

Area = ∫₀¹ (x - x²) dx = 1/2 - 1/3 = 1/6

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

JEE Advanced Calculus in other years

Calculus 2026

More JEE Advanced Calculus Questions

The value of lim(x→0) (sin x)/x is:

2026
easy
mcq

If ∫₀^1 (x⁴(1-x)⁴)/(1+x²) dx = 22/7 - π, find the value of 7∫₀^1 (x⁴(1-x)⁴)/(1+x²) dx + 7π rounded to nearest integer.

2026
hard
integer

Evaluate ∫₀³ x² dx

2025
hard
numerical_value

The value of the integral ∫₀^π x·sin²(x)·cos(x) dx is:

2025
hard
mcq
View all Calculus questions

Other Mathematics Topics for JEE Advanced

Algebra

2 questions

Vectors & 3D Geometry

2 questions