$\int_0^3 x^2 \, dx = \left[\frac{x^3}{3}\right]_0^3 = \frac{27}{3} - \frac{0}{3} = 9$
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JEE Advanced 2025 — Mathematics Calculus
hard
numerical_value
2025
Official previous-year question
Verified 30 May 2026.
Question
Evaluate $\int_0^3 x^2 \, dx$
Answer
Exact answer: 9
Solution
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