Correct Option: 4
The question seeks to determine if p>q.
Consider Statement-1: p×q>0. This condition implies that p and q must have the same sign (both positive or both negative).
- If p=2 and q=1, then p×q=2>0, and p>q.
- If p=-2 and q=-1, then p×q=2>0, and p<q.
Since both p>q and p<q are possible outcomes, Statement-1 alone is insufficient to answer the question.
Consider Statement-2: p2>q2. This condition implies that ∣p∣>∣q∣.
- If p=2 and q=1, then p2=4>q2=1, and p>q.
- If p=-2 and q=1, then p2=4>q2=1, and p<q.
Since both p>q and p<q are possible outcomes, Statement-2 alone is insufficient to answer the question.
Consider both Statement-1 and Statement-2 together: From Statement-1, p and q have the same sign. From Statement-2, ∣p∣>∣q∣.
- If p and q are both positive: Given ∣p∣>∣q∣, it follows that p>q. (e.g., p=2, q=1).
- If p and q are both negative: Given ∣p∣>∣q∣, it implies that p is numerically larger than q but negative. Consequently, p<q. (e.g., p=-2, q=-1, where ∣−2∣>∣−1∣ but −2<−1).
As the combined statements allow for scenarios where p>q and scenarios where p<q, the question "Is p greater than q?" cannot be definitively answered even by using both statements together.
Incorrect Options:
Options 1, 2, and 3 are incorrect because, as demonstrated, neither statement alone nor both statements together provide a conclusive answer to whether p>q.