IAS 2022 — CSAT Reasoning

2022mcqmedium

Which date of June 2099 among the following in Sunday?

Official previous-year question

Verified 2 Aug 2026.

Options

Did you get this right?

Solution

Correct Option (2)

To determine the day of the week for a specific date, the concept of "odd days" is utilized. The reference point is given as January 1, 2001, which was a Monday.

The calculation proceeds as follows:

Number of years: The period spans from 2001 to 2099, encompassing 99 years.
Leap years: Within this 99-year period (2001-2099), the leap years are 2004, 2008, ..., 2096. The number of leap years is $(2096 - 2004)/4 + 1 = 23 + 1 = \textbf{24}$ .
Non-leap years: The number of non-leap years is $99 - 24 = \textbf{75}$ .
Odd days from years: Each leap year contributes 2 odd days, and each non-leap year contributes 1 odd day. Total odd days from these 99 years = $(24 \times 2) + (75 \times 1) = 48 + 75 = \textbf{123}$ .
Odd days from months in 2099 (up to June 1):
- January (31 days): 3 odd days
- February (28 days, as 2099 is not a leap year): 0 odd days
- March (31 days): 3 odd days
- April (30 days): 2 odd days
- May (31 days): 3 odd days
- June (up to 1st day): 1 odd day
Total odd days from months = $3 + 0 + 3 + 2 + 3 + 1 = \textbf{12}$ $3 + 0 + 3 + 2 + 3 + 1 = 12$ .
Total odd days: Sum of odd days from years and months = $123 + 12 = \textbf{135}$ .
Net odd days: To find the net change in day, divide the total odd days by 7 and take the remainder. $135 \div 7 = 19$ with a remainder of $\textbf{2}$ . Thus, there are 2 net odd days.

Since January 1, 2001, was a Monday, June 1, 2099, will be Monday + 2 days = Wednesday.

Now, we determine which date in June 2099 is a Sunday:

June 1 = Wednesday
June 2 = Thursday
June 3 = Friday
June 4 = Saturday
June 5 = Sunday

Therefore, June 5, 2099, is a Sunday.

Incorrect Options:

Option 1 (4): If June 1, 2099, is Wednesday, then June 4, 2099, would be a Saturday.
Option 3 (6): If June 1, 2099, is Wednesday, then June 6, 2099, would be a Monday.
Option 4 (7): If June 1, 2099, is Wednesday, then June 7, 2099, would be a Tuesday.

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Two identical straight rods are painted in five distinct colours so that each of them gets divided into five equal parts along the length. In one of them, the portions are marked P1, P2, P3, P4 and P5 (not necessarily in that order) whereas in the other, they are marked Q1, Q2, Q3, Q4 and Q5 (not necessarily in that order). When the rods are kept parallel to each other side by side, P1 and Q3 match, P4 matches Q1 or Q2, and Q4 matches P3 or P5. If Q3 and Q5 are adjacent, which of the following is/are possible? 1. Q3 is marked at the middle portion of the straight rod. 2. P2 is marked at one of the extreme portions of the straight rod. Select the answer using the code given below.

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Seven cubes are identical in shape. Out of these, the weight of each of the six cubes is equal and the weight of the remaining cube is less than the weight of any other cube. A balance is used to identify the lightest cube. What is the minimum number of attempts required to distinguish the odd cube with certainty?

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IAS 2022 — CSAT Reasoning

2022mcqmedium

Which date of June 2099 among the following in Sunday?

Official previous-year question

Verified 2 Aug 2026.

Options

Did you get this right?

Solution

Correct Option (2)

To determine the day of the week for a specific date, the concept of "odd days" is utilized. The reference point is given as January 1, 2001, which was a Monday.

The calculation proceeds as follows:

Number of years: The period spans from 2001 to 2099, encompassing 99 years.
Leap years: Within this 99-year period (2001-2099), the leap years are 2004, 2008, ..., 2096. The number of leap years is $(2096 - 2004)/4 + 1 = 23 + 1 = \textbf{24}$ .
Non-leap years: The number of non-leap years is $99 - 24 = \textbf{75}$ .
Odd days from years: Each leap year contributes 2 odd days, and each non-leap year contributes 1 odd day. Total odd days from these 99 years = $(24 \times 2) + (75 \times 1) = 48 + 75 = \textbf{123}$ .
Odd days from months in 2099 (up to June 1):
- January (31 days): 3 odd days
- February (28 days, as 2099 is not a leap year): 0 odd days
- March (31 days): 3 odd days
- April (30 days): 2 odd days
- May (31 days): 3 odd days
- June (up to 1st day): 1 odd day
Total odd days from months = $3 + 0 + 3 + 2 + 3 + 1 = \textbf{12}$ $3 + 0 + 3 + 2 + 3 + 1 = 12$ .
Total odd days: Sum of odd days from years and months = $123 + 12 = \textbf{135}$ .
Net odd days: To find the net change in day, divide the total odd days by 7 and take the remainder. $135 \div 7 = 19$ with a remainder of $\textbf{2}$ . Thus, there are 2 net odd days.

Since January 1, 2001, was a Monday, June 1, 2099, will be Monday + 2 days = Wednesday.

Now, we determine which date in June 2099 is a Sunday:

June 1 = Wednesday
June 2 = Thursday
June 3 = Friday
June 4 = Saturday
June 5 = Sunday

Therefore, June 5, 2099, is a Sunday.

Incorrect Options:

Option 1 (4): If June 1, 2099, is Wednesday, then June 4, 2099, would be a Saturday.
Option 3 (6): If June 1, 2099, is Wednesday, then June 6, 2099, would be a Monday.
Option 4 (7): If June 1, 2099, is Wednesday, then June 7, 2099, would be a Tuesday.

Your note

IAS Reasoning in other years

Reasoning 2026 Reasoning 2025 Reasoning 2024 Reasoning 2023 Reasoning 2021 Reasoning 2020 Reasoning 2019 Reasoning 2018 Reasoning 2017 Reasoning 2016 Reasoning 2015 Reasoning 2014

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IAS 2022 — CSAT Reasoning

Options

Did you get this right?

Solution

Correct Option (2)

Incorrect Options:

Your note

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IAS 2022 — CSAT Reasoning

Options

Did you get this right?

Solution

Correct Option (2)

Incorrect Options:

Your note

IAS Reasoning in other years

More IAS Reasoning questions

Other CSAT topics for IAS

Comprehension

Maths

Keep practicing Reasoning