Correct Option (B)
Let Meera's age in 2002 be x years.
According to the problem statement, Meenu's age in 2002 was one-third of Meera's age.
- Meenu's age in 2002 = 31×x=3x years.
Eight years later, in 2010, their ages would be:
- Meera's age in 2010 = (x+8) years.
- Meenu's age in 2010 = (3x+8) years.
In 2010, Meenu's age was half the age of Meera. This can be expressed as:
3x+8=21(x+8)
To solve for x:
3x+8=2x+4
Rearranging the terms to isolate x:
8−4=2x−3x
4=63x−2x
4=6x
x=24
Therefore, Meera's age in 2002 was 24 years.
Meenu's age in 2002 was 31×24=8 years.
To find Meenu's year of birth, subtract her age in 2002 from the year 2002:
Meenu's year of birth = 2002 - 8 = 1994.
Incorrect Options:
The calculated year of birth for Meenu is 1994. Options A (1992), C (1996), and D (1998) are inconsistent with the derived ages based on the given conditions.