Correct Option (C)
Given that B is selected and Y is rejected. According to the problem statement, B cannot play with W. Therefore, if B is selected, W must be rejected from the team.
The available players are A, B, C (males) and W, X, Y, Z (females).
Based on the conditions:
- B is selected.
- Y is rejected.
- W is rejected (because B is selected).
The players remaining for selection are A, C (males) and X, Z (females). We need to select 3 more players to form a team of four.
The team must have at least two males. Since B is already selected, we need to select at least one more male from A or C.
Let us consider selecting both remaining males, A and C. This forms a core of three males (A, B, C), satisfying the "at least two males" condition.
Now, one more player is needed from the remaining females (X, Z).
The problem states that C cannot play with Z. Since C is part of our selected core (A, B, C), Z cannot be selected as the fourth player.
Therefore, the only eligible female remaining is X.
The resulting team is A, B, C, X.
This team satisfies all conditions:
- It has four players.
- It has three males (A, B, C), fulfilling the "at least two males" requirement.
- All player conflicts are avoided: B is not with W, C is not with Z, and W is not with Y (as W and Y are not in the team).
Incorrect Options:
The initial conditions are: B is selected, Y is rejected.
Option (A) A, B, C and W:
- This option includes W. However, the problem states that B cannot play with W. Since B is selected, W cannot be part of the team.
Option (B) A, B, C and Z:
- This option includes C and Z. However, the problem states that C cannot play with Z. Therefore, C and Z cannot be in the same team.
Option (D) A, W, Y and Z:
- This option violates the initial conditions: B is selected, but not included in this option. Y is rejected, but included in this option. W is rejected (due to B's selection), but included in this option.
- Additionally, W cannot play with Y, and both are present in this option, creating another conflict.