Correct Option
The given number N² = 12345678987654321 exhibits a specific pattern: it sequentially increases from 1 to 9 and then decreases back to 1. This form is characteristic of the square of a repunit, which is a number consisting solely of the digit 1.
Specifically, if a repunit consists of 'k' digits (i.e., 'k' ones), its square will form a number that ascends from 1 to 'k' and then descends back to 1. For example:
- 1² = 1 (k=1)
- 11² = 121 (k=2)
- 111² = 12321 (k=3)
In the given N² = 12345678987654321, the highest digit reached in the sequence is 9. This indicates that N is a repunits composed of nine 1s.
Therefore, N = 111,111,111, which is a number with 9 digits.
Incorrect Options
Options 1 (8), 3 (10), and 4 (11) are incorrect because they do not align with the observed pattern of N².
- If N had 8 digits (i.e., N = 11,111,111), then N² would be 123456787654321, where the peak digit is 8. This does not match the given N².
- If N had 10 digits (i.e., N = 1,111,111,111), then N² would be a number with 19 digits, where the sequence would theoretically ascend to 10. The given N² has 17 digits and peaks at 9.
- If N had 11 digits (i.e., N = 11,111,111,111), then N² would be a number with 21 digits, which is inconsistent with the given N².
The unique structure of N² = 12345678987654321 directly corresponds to the square of a 9-digit repunit.