Correct Option
The sum of digits in the number (10n + 1) is 2 for any whole number n.
- If n = 0, then 100 + 1 = 1 + 1 = 2. The sum of digits is 2.
- If n is a positive integer (n > 0), the number 10n consists of the digit '1' followed by 'n' zeros (e.g., 101 = 10, 102 = 100, 103 = 1000).
- Therefore, (10n + 1) will consist of the digit '1' at the (n+1)th place (from the right, starting at 0) and the digit '1' at the units place, with 'n-1' zeros in between (e.g., 101 + 1 = 11; 102 + 1 = 101; 103 + 1 = 1001).
- The sum of the digits in such a number will always be 1 + 0 + ... + 0 + 1 = 2.
- This condition holds true for all whole numbers (0, 1, 2, 3, ...).
Incorrect Options
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Option A (For n = 0 only): This is incorrect because the condition also holds for all positive integers (e.g., n=1, 2, 3, ...), not just for n=0.
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Option C (For any positive integer n only): This is incorrect because it excludes n=0, for which the sum of digits in (100 + 1) is 2.
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Option D (For any real number n): This is incorrect. The concept of "sum of digits" is typically applied to integers or numbers with a finite decimal representation. For non-integer real values of n (e.g., n=0.5), 10n + 1 would result in a non-integer value (e.g., 100.5 + 1 = √10 + 1 ≈ 4.1622...), for which the sum of digits is not 2 and the definition of 'sum of digits' becomes ambiguous in the context of the question.