Statistics & Applications PYQ — Page 7

A 95% confidence interval for a population mean was reported to be 152 to 160. If standard deviation $\sigma = 15$ . Then the sample size is : ($Z_{0.025}$=1.96)

Consider the following hypothesis test:- H₀: μ = 20 H₁: μ ≠ 20 A sample of 40 provided a sample mean of 19. The standard deviation is 3. Then the value of the t-test statistic is:

Match List-I with List-II | List-I | List-II | |---|---| | (A) The chance of observing a specific outcome in an experiment | (I) Parameter | | (B) A method used to estimate the population parameters | (II) Estimation | | (C) A value that describes an entire population | (III) Statistic | | (D) A measurable characteristic of a sample | (IV) Probability distribution | Choose the correct answer from the options given below:

In a survey for a sample of 300 individuals, 180 persons gave responses 'Yes' and 100 gave responses 'No' and 20 gave "No response". Then point estimate of proposition in the population who responded "Yes" is

Consider the following data: | Year (x) | 2010 | 2011 | 2012 | 2013 | 2014 | |---|---|---|---|---|---| | Sale (in crore Rs.) (y) | 9 | 18 | 21 | 29 | 38 | A straight line trend by the method of least square is:

For the given values 8, 10, 12, 14, 16; the three-year moving averages are:

A piece of machinery is bought for Rs. 50,000. In the first year, it depreciates by 15%, and in each subsequent year, the depreciation rate increases by 5% from the previous year. The value of machinery after 3 years will be:

Increase in the number of patients in the hospitals due to heat stroke is:

A man takes a personal loan worth Rs.3,00,000 at an interest rate of 6% per annum compounded monthly to be repaid by equal monthly installments in 3 years, then the EMI using flat rate method will be:-

In reference to Inferential Statistics, for 20 degrees of freedom, the least statistical t-value among the given below is:

The effective rate equivalent to a nominal rate of 12% compounded quarterly is: (Given $(1.03)^4=1.1256$)

If an investment value get doubled in 10 years then its compound annual growth rate (CAGR) is: (Given $2^{1/10} = 1.0729$)

Ramesh plans to save some amount required after 10 years for higher studies of his son. He expects the cost of these studies to be Rs.1,00,000. How much should he save at the beginning of each year to accumulate this amount at the end of 10 years, if the interest rate is 12% compounded annually. (Given $(1.12)^{11}=3.477$)

The scrap value of a machine costing ₹ 75,000 after 4 years of use is ₹ 25000. Using straight line method the annual depreciation of the machine is:

If a 99% confidence interval states that the population mean is greater than 100 and less than 400. Then the sample mean and margin of error respectively are:

The effective rate of return equivalent to a nominal rate of 12% per annum compounded quarterly is: [Given that: $(1.03)^4 ≈ 1.1255$]

In reference to Inferential Statistics, if $\bar{x}$ is a sample mean of random data $\{x_i\}_{i=1}^n$ and $n$ is the sample size, then the formula $\frac{1}{n-1}\sum_{i=0}^n(x_i - \bar{x})^2$ represents

For the given five values, 3.6, 4.3, 4.3, 3.4, 4.4, the three years moving averages are:

Match List-I with List-II | List-I | List-II | |---|---| | (A) The measurable characteristic of a population is called | (i) Sample | | (B) The measurable characteristic of a sample is called | (ii) Alternative hypothesis | | (C) A smaller group of a population selected to represent a population is called | (iii) Parameter | | (D) The assumption made opposite to the null hypothesis is called | (iv) Statistic | Choose the correct answer from the options given below:

An investment of ₹ 3,00,000 becomes ₹ 4,50,000 in 5 years, then the compound annual growth rate (CAGR) is equal to: [Given that: $(1.5)^{1/5} = 1.084$]

At what rate of interest will the present value of a perpetuity of ₹ 600 payable at the end of every 3 months be ₹ 18,000?

The annual depreciation of a car is ₹ 40,000. If the scrap value of the car after 15 years is ₹ 50,000, then the original cost of the car using linear method is

A random sample of 100 individuals provides 25 positive responses. Then the point estimate of the population proportion with "positive" responses is:

Ram wishes to purchase a house for ₹ 15,00,000 and made a down payment of ₹ 5,00,000. If he can amortize the balance at 9% per annum compounded monthly for 25 years, then his EMI is: [Given $(1.0075)^{300} ≈ 9.41$]