Let's find ∣b∣ using the given conditions.
We start by expanding the dot product (a−b)⋅(a+b):
(a−b)⋅(a+b)=a⋅a+a⋅b−b⋅a−b⋅b
Since dot product is commutative (a⋅b=b⋅a):
(a−b)⋅(a+b)=a⋅a−b⋅b=∣a∣2−∣b∣2=27
Using the relationship ∣a∣=2∣b∣:
∣a∣2=(2∣b∣)2=4∣b∣2
Substituting into our equation:
4∣b∣2−∣b∣2=27
3∣b∣2=27
∣b∣2=9
∣b∣=3
Therefore, ∣b∣=3.