The vector equation of line passing through (2, -1, 3) and perpendicular to the lines x-2 3 = y-1 1 = z+2 2 and x+3 -4 = y-5 -3 = z+1 2 is (Here λ is…
CUET UG 2025 — Mathematics Geometry
The vector equation of line passing through (2, -1, 3) and perpendicular to the lines
3x−2=1y−1=2z+2 and −4x+3=−3y−5=2z+1 is
(Here λ is a parameter)
Held on 29 May 2025 · Verified 13 Jul 2026.
Options
- A
r=(2i^−j^+3k^)+λ(8i^−14j^−5k^)
- B
r=(−2i^+j^−3k^)+λ(8i^−14j^−5k^)
- C
r=(−8i^−14j^−5k^)+λ(−2i^+j^+3k^)
- D
r=(8i^−14j^−5k^)+λ(2i^−j^+3k^)
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