Let x=tanθ, so 1+x2=secθ. Then (secθ−1)/tanθ=(1−cosθ)/sinθ=tan(θ/2). Hence tan−1(tan(θ/2))=θ/2=(1/2)tan−1x.
CUET UG 2023 — Mathematics Geometry
The simplest form of tan−1x1+x2−1, x=0 is:
Held on 23 May 2023 · Verified 13 Jul 2026.
tan−1x
x
21tan−1x
1+x2
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Consider the line $\vec{r} = -2\hat{i} + 3\hat{j} + \hat{k} + \lambda(5\hat{i} - 3\hat{j} - \hat{k})$. Match List-I with List-II | List-I | List-II | |---|---| | (A) A point on the given line | (I) $\left(\frac{5}{\sqrt{35}}, \frac{-3}{\sqrt{35}}, \frac{-1}{\sqrt{35}}\right)$ | | (B) Direction ratios of the given line | (II) (2, 3, 1) | | (C) Direction cosines of the given line | (III) (5, -3, -1) | | (D) Direction ratios of a line perpendicular to given line | (IV) (-2, 3, 1) | Choose the correct answer from the options given below:
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