Both lines have direction b=(2,−1,1), so they are parallel.
a2−a1=(1−a,−3,2).
(a2−a1)×b=(−1,3+a,5+a).
Distance: 61+(3+a)2+(5+a)2=635.
Solving: 2a2+16a=0⇒a=0 or a=−8.
If the shortest distance between the lines l_1 and l_2 given by = a i + 2 j - k + λ(2 i - j + k) and = i - j + k + μ(2 i - j + k) is √ 35 6 units,…
CUET UG 2023 — Mathematics Geometry
2023mcqhard
If the shortest distance between the lines l1 and l2 given by r=ai^+2j^−k^+λ(2i^−j^+k^) and r=i^−j^+k^+μ(2i^−j^+k^) is 635 units, the values of 'a' can be :
Official previous-year question
Held on 22 May 2023 · Verified 13 Jul 2026.
Options
- A
0, -8
- B
0, 8
- C
2, 6
- D
-2, 6
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