Line passes through (1,−1,1) with direction d=(−1,2,3).
Vector from (0,1,0) to (1,−1,1): v=(1,−2,1).
Normal: n=v×d=(−6−2,−3−1,2−2)=(−8,−4,0).
Simplify by −4: (2,1,0).
Plane: 2(x−0)+1(y−1)+0(z)=0⇒2x+y−1=0.
The equation of plane that contains line x - 1 -1 = y + 1 2 = z - 1 3 and also pass through point (0, 1, 0) is :
CUET UG 2022 — Mathematics Geometry
2022mcqmedium
The equation of plane that contains line −1x−1=2y+1=3z−1 and also pass through point (0,1,0) is :
Official previous-year question
Held on 7 Aug 2022 · Verified 13 Jul 2026.
Options
- A
2x+y−1=0
- B
2x+y+z=0
- C
2x+y−z−1=0
- D
4x+y+4z−1=0
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