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Find the root of perpendicular from origin to the line x - 1 3 = y - 2 -2 = z + 1 3.

CUET UG 2022 — Mathematics Geometry

2022mcqmedium

Find the root of perpendicular from origin to the line x−13=y−2−2=z+13\frac{x - 1}{3} = \frac{y - 2}{-2} = \frac{z + 1}{3}3x−1​=−2y−2​=3z+1​.

Official previous-year question

Held on 7 Aug 2022 · Verified 13 Jul 2026.

Options

  1. A

    (811,2411,−1411)\left(\frac{8}{11}, \frac{24}{11}, \frac{-14}{11}\right)(118​,1124​,11−14​)

  2. B

    (111,211,−711)\left(\frac{1}{11}, \frac{2}{11}, \frac{-7}{11}\right)(111​,112​,11−7​)

  3. C

    (1711,1811,−511)\left(\frac{17}{11}, \frac{18}{11}, \frac{-5}{11}\right)(1117​,1118​,11−5​)

  4. D

    (711,1011,−1011)\left(\frac{7}{11}, \frac{10}{11}, \frac{-10}{11}\right)(117​,1110​,11−10​)

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