R={(1,6),(2,7),(3,8)}.
Not reflexive: (1,1)∈/R.
Not symmetric: (1,6)∈R but (6,1)∈/R.
Transitive vacuously: no (a,b),(b,c) pairs exist where b is the first element of another pair.
If x is the least positive integer satisfying 100≡x(mod6), then (2x+1) is equal to :
Held on 15 Jun 2023 · Verified 13 Jul 2026.
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