Total pens = 14. With replacement, p=144=72, q=75, n=3.
P(X=0)=(5/7)3=125/343 (matches row III).
P(X=1)=3(2/7)(5/7)2=150/343 (matches row IV).
P(X=2)=3(2/7)2(5/7)=60/343 (matches row II).
P(X=3)=(2/7)3=8/343 (matches row I).
Match: A-III, B-IV, C-II, D-I.