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Match List - I with List - II. | List - I | List - II | |----------|-----------| | (A) The minimum value of f(x) = 8x^2 - 4x + 7 is | (I) 48 | | (B)…

CUET UG 2023 — Mathematics Applied-Mathematics

2023mcqhard

Match List - I with List - II.

List - I List - II
(A) The minimum value of f(x)=8x2−4x+7f(x) = 8x^2 - 4x + 7f(x)=8x2−4x+7 is (I) 48
(B) The maximum value of f(x)=x+1xf(x) = x + \frac{1}{x}f(x)=x+x1​, x<0x < 0x<0 is (II) 13
(C) The maximum slope of the curve y=−2x3+6x2+7x+26y = -2x^3 + 6x^2 + 7x + 26y=−2x3+6x2+7x+26 is (III) −2-2−2
(D) The minimum value of f(x)=x2+128xf(x) = x^2 + \frac{128}{x}f(x)=x2+x128​ is (IV) 132\frac{13}{2}213​

Choose the correct answer from the options given below :

Official previous-year question

Held on 15 Jun 2023 · Verified 13 Jul 2026.

Options

  1. A

    (A)-(I), (B)-(III), (C)-(II), (D)-(IV)

  2. B

    (A)-(IV), (B)-(III), (C)-(II), (D)-(I)

  3. C

    (A)-(II), (B)-(IV), (C)-(I), (D)-(III)

  4. D

    (A)-(III), (B)-(IV), (C)-(II), (D)-(I)

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