Points are collinear if 2−1a143111=0.
Expand: 2(4−3)−1(−1−a)+1(−3−4a)=0.
2+1+a−3−4a=0⇒−3a=0⇒a=0.
If y=log(e5x5), then dx2d2y is,
Held on 15 Jun 2023 · Verified 13 Jul 2026.
x2−5
x4−20
e2x3
e2−20x3
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