Let x=tanθ. Then (1−x2)/(1+x2)=cos2θ. So y=sin−1(cos2θ)=π/2−2θ=π/2−2tan−1x. Differentiating: dy/dx=−2/(1+x2).
If A′=[−2132] and B=[−1203]
then (3A+2B)′ is :
Held on 23 May 2023 · Verified 13 Jul 2026.
[−21510]
[8−21312]
[−831312]
[7−31012]
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