Skip to main content

If A = … and B = …, then AB is equals to :

CUET UG 2022 — Mathematics Applied-Mathematics

2022mcqeasy

If A=[n000n000n]A = \begin{bmatrix} n & 0 & 0 \\ 0 & n & 0 \\ 0 & 0 & n \end{bmatrix}A=​n00​0n0​00n​​ and B=[a1a2a3b1b2b3c1c2c3]B = \begin{bmatrix} a_1 & a_2 & a_3 \\ b_1 & b_2 & b_3 \\ c_1 & c_2 & c_3 \end{bmatrix}B=​a1​b1​c1​​a2​b2​c2​​a3​b3​c3​​​, then AB is equals to :

Official previous-year question

Held on 11 Aug 2022 · Verified 13 Jul 2026.

Options

  1. A

    B

  2. B

    nB

  3. C

    BnB^nBn

  4. D

    A+B

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

CUET UG Applied-Mathematics in other years

More CUET UG Applied-Mathematics questions

Other Mathematics topics for CUET UG

Keep practicing Applied-Mathematics

Work through every CUET UG Applied-Mathematics PYQ, year by year.

Browse all Mathematics topics