Match List-I with List-II | List-I | List-II | |---|---| | (Figures, etc.) | (Area/Volume/Diagonal etc.) | | (A) Surface area of Cube | (I) $\pi(R^2 - r^2)$ | | (B) Volume of Right pyramid | (II) $a\sqrt{2}$ | | (C) Area of Circular Ring | (III) $6a^2$ | | (D) Diagonal of Square | (IV) $\frac{1}{3}$(area of base) × height | Choose the correct answer from the options given below:

CUET UG 2025 — General Test Geometry

2025mcqeasy

Match List-I with List-II

List-I	List-II
(Figures, etc.)	(Area/Volume/Diagonal etc.)
(A) Surface area of Cube	(I) $\pi(R^2 - r^2)$
(B) Volume of Right pyramid	(II) $a\sqrt{2}$
(C) Area of Circular Ring	(III) $6a^2$
(D) Diagonal of Square	(IV) $\frac{1}{3}$ (area of base) × height

Choose the correct answer from the options given below:

Official previous-year question

Held on 15 May 2025 · Verified 13 Jul 2026.

Options

A
(A) - (I), (B) - (II), (C) - (III), (D) - (IV)
B
(A) - (II), (B) - (III), (C) - (IV), (D) - (I)
C
(A) - (III), (B) - (IV), (C) - (I), (D) - (II)
D
(A) - (IV), (B) - (I), (C) - (II), (D) - (III)

Did you get this right?

Solution

A cube has 6 faces (top, bottom, and 4 sides).

Each face is a square with area $a^2$ .

Total surface area $= 6 \times a^2$

$= 6a^2$

(A) matches with (III)

The volume formula for any pyramid is:

Volume $= \dfrac{1}{3} \times (\text{area of base}) \times \text{height}$

(B) matches with (IV)

A circular ring is the region between two circles.

The larger circle has radius $R$ and the smaller circle has radius $r$ .

Area $= \pi R^2 - \pi r^2$

$= \pi(R^2 - r^2)$

For a square with side $a$ , using the Pythagorean theorem:

$\text{diagonal}^2 = a^2 + a^2$

$\text{diagonal}^2 = 2a^2$

$\text{diagonal} = \sqrt{2a^2}$

$= a\sqrt{2}$

(D) matches with (II)

The correct matching is:

(A) - (III), (B) - (IV), (C) - (I), (D) - (II)

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List-I

List-II

(Figures, etc.)

(Area/Volume/Diagonal etc.)

(A) Surface area of Cube

(I)

\pi(R^2 - r^2)

(B) Volume of Right pyramid

(II)

a\sqrt{2}

(III)

6a^2

(D) Diagonal of Square

(IV)

\frac{1}{3}

(area of base) × height

Solution

A cube has 6 faces (top, bottom, and 4 sides).

Each face is a square with area $a^2$ .

Total surface area $= 6 \times a^2$

$= 6a^2$

(A) matches with (III)

The volume formula for any pyramid is:

Volume $= \dfrac{1}{3} \times (\text{area of base}) \times \text{height}$

(B) matches with (IV)

A circular ring is the region between two circles.

The larger circle has radius $R$ and the smaller circle has radius $r$ .

Area $= \pi R^2 - \pi r^2$

$= \pi(R^2 - r^2)$

For a square with side $a$ , using the Pythagorean theorem:

$\text{diagonal}^2 = a^2 + a^2$

$\text{diagonal}^2 = 2a^2$

$\text{diagonal} = \sqrt{2a^2}$

$= a\sqrt{2}$

(D) matches with (II)

The correct matching is:

(A) - (III), (B) - (IV), (C) - (I), (D) - (II)

CUET UG 2025 — General Test Geometry

Options

Did you get this right?

Solution

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CUET UG 2025 — General Test Geometry

Options

Did you get this right?

Solution

Your note

CUET UG Geometry in other years

More CUET UG Geometry questions

Other General Test topics for CUET UG

General Knowledge

Logical Reasoning

Arithmetic

Quantitative Reasoning

Current Affairs

Keep practicing Geometry