The centroid of a triangle with vertices (x1,y1), (x2,y2), and (x3,y3) is given by:
Centroid =(3x1+x2+x3,3y1+y2+y3)
Given vertices: (5,4), (−2,4), and (x,y)
Given centroid: (5,6)
For the x-coordinate of the centroid:
5=35+(−2)+x
5=33+x
15=3+x
x=12
For the y-coordinate of the centroid:
6=34+4+y
6=38+y
18=8+y
y=10
Therefore, the third vertex is (12,10).