The distance between points (2, -2) and (5, k) is 5 units.
Using the distance formula:
Distance=(x2−x1)2+(y2−y1)2
5=(5−2)2+(k−(−2))2
5=(3)2+(k+2)2
5=9+(k+2)2
Squaring both sides:
25=9+(k+2)2
(k+2)2=16
Taking the square root of both sides:
k+2=±4
This gives two possible values:
k+2=4
k=2
or
k+2=−4
k=−6
The possible values of k are 2 and -6.
Therefore, one of the possible values of k is 2.