From 2πr1=396, r1=63 m. From 2πr2=132, r2=21 m.
New radius =63+21=84 m.
Area =πr2=722×84×84=22176 m2.
The circumference of a circular field is 396 m and that of the other circular field is 132 m. Find the area (in m2) of the third circular field whose radius is the sum of the radii of the first two fields. Take π=722
Held on 1 Jun 2023 · Verified 13 Jul 2026.
13860
19536
22176
23984
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