CUET UG 2025 — General Test Arithmetic

Let the cost price of one mobile phone be $x$x.

Total cost price of both mobile phones $= 2x$=2x

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The first mobile was sold at a profit of 20%.

Selling price of first mobile $= x + 0.20x$=x+0.20x

$$= 1.20x$$=1.20x

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The second mobile was sold at Rs. 1520 less than the first mobile.

Selling price of second mobile $= 1.20x - 1520$=1.20x−1520

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Total selling price of both mobiles $= 1.20x + (1.20x - 1520)$=1.20x+(1.20x−1520)

$$= 2.40x - 1520$$=2.40x−1520

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The overall profit earned was 1%.

Total selling price $=$= Total cost price $+ 1\%$+1% of total cost price

$$2.40x - 1520 = 2x + 0.01(2x)$$2.40x−1520=2x+0.01(2x)

$$2.40x - 1520 = 2x + 0.02x$$2.40x−1520=2x+0.02x

$$2.40x - 1520 = 2.02x$$2.40x−1520=2.02x

$$2.40x - 2.02x = 1520$$2.40x−2.02x=1520

$$0.38x = 1520$$0.38x=1520

$$x = \dfrac{1520}{0.38}$$x=0.381520​

$$x = 4000$$x=4000

Therefore, the cost price of one mobile phone is Rs. 4000.