CUET UG 2025 — General Test Arithmetic

Simple Interest is calculated using:

$$SI = \dfrac{P \times R \times T}{100}$$SI=100P×R×T​

where $P$P = Principal, $R$R = Rate of interest per year (%), $T$T = Time (years)

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For case (A): $P = 6600$P=6600, $R = 5$R=5, $T = 2$T=2

$$SI = \dfrac{6600 \times 5 \times 2}{100}$$SI=1006600×5×2​

$$SI = \dfrac{66000}{100}$$SI=10066000​

$$SI = 660$$SI=660

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For case (B): $P = 200$P=200, $R = 6$R=6, $T = 5$T=5

$$SI = \dfrac{200 \times 6 \times 5}{100}$$SI=100200×6×5​

$$SI = \dfrac{6000}{100}$$SI=1006000​

$$SI = 60$$SI=60

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For case (C): $P = 840$P=840, $R = 5$R=5, $T = 4$T=4

$$SI = \dfrac{840 \times 5 \times 4}{100}$$SI=100840×5×4​

$$SI = \dfrac{16800}{100}$$SI=10016800​

$$SI = 168$$SI=168

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For case (D): $P = 5000$P=5000, $R = 12$R=12, $T = 2$T=2

$$SI = \dfrac{5000 \times 12 \times 2}{100}$$SI=1005000×12×2​

$$SI = \dfrac{120000}{100}$$SI=100120000​

$$SI = 1200$$SI=1200

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Comparing the simple interests:

(D) = Rs 1200

(A) = Rs 660

(C) = Rs 168

(B) = Rs 60

Therefore, the decreasing order is: (D), (A), (C), (B)