Arrange the simple interest of the following cases in decreasing order- (A) The simple interest on Rs 6600 at 5% per annum for 2 yrs. (B) The simple interest on Rs 200 at 6% per annum for 5 yrs. (C) The simple interest on Rs 840 at 5% per annum for 4 yrs. (D) The simple interest on Rs 5000 at 12% per annum for 2 yrs. Choose the correct answer from the options given below:

Arrange the simple interest of the… - CUET UG 2025 General Test PYQ

CUET UG 2025 — General Test Arithmetic

2025mcqmedium

Arrange the simple interest of the following cases in decreasing order-

(A) The simple interest on Rs 6600 at 5% per annum for 2 yrs.

(B) The simple interest on Rs 200 at 6% per annum for 5 yrs.

(D) The simple interest on Rs 5000 at 12% per annum for 2 yrs.

Choose the correct answer from the options given below:

Official previous-year question

Held on 13 May 2025 · Verified 13 Jul 2026.

Options

A
(A), (B), (C), (D)
B
(B), (A), (D), (C)
C
(B), (A), (C), (D)
D
(D), (A), (C), (B)

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Solution

Simple Interest is calculated using:

$SI = \dfrac{P \times R \times T}{100}$

where $P$ = Principal, $R$ = Rate of interest per year (%), $T$ = Time (years)

For case (A): $P = 6600$ , $R = 5$ , $T = 2$

$SI = \dfrac{6600 \times 5 \times 2}{100}$

$SI = \dfrac{66000}{100}$

$SI = 660$

For case (B): $P = 200$ , $R = 6$ , $T = 5$

$SI = \dfrac{200 \times 6 \times 5}{100}$

$SI = \dfrac{6000}{100}$

$SI = 60$

For case (C): $P = 840$ , $R = 5$ , $T = 4$

$SI = \dfrac{840 \times 5 \times 4}{100}$

$SI = \dfrac{16800}{100}$

$SI = 168$

For case (D): $P = 5000$ , $R = 12$ , $T = 2$

$SI = \dfrac{5000 \times 12 \times 2}{100}$

$SI = \dfrac{120000}{100}$

$SI = 1200$

Comparing the simple interests:

(D) = Rs 1200

(A) = Rs 660

(B) = Rs 60

Therefore, the decreasing order is: (D), (A), (C), (B)

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