CUET UG 2025 — General Test Arithmetic

The first case involves Rs 1550 for 2 years, and the second case involves Rs 1450 for 2 years at the same rate. The interest on Rs 1550 is Rs 20 more than the interest on Rs 1450.

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Simple Interest $= \dfrac{P \times R \times T}{100}$=100P×R×T​

For Rs 1550:

$$SI_1 = \dfrac{1550 \times R \times 2}{100}$$SI1​=1001550×R×2​

For Rs 1450:

$$SI_2 = \dfrac{1450 \times R \times 2}{100}$$SI2​=1001450×R×2​

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The interest on Rs 1550 is Rs 20 more than the interest on Rs 1450:

$$SI_1 = SI_2 + 20$$SI1​=SI2​+20

$$\dfrac{1550 \times R \times 2}{100} = \dfrac{1450 \times R \times 2}{100} + 20$$1001550×R×2​=1001450×R×2​+20

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$$\dfrac{3100R}{100} = \dfrac{2900R}{100} + 20$$1003100R​=1002900R​+20

$$\dfrac{3100R}{100} - \dfrac{2900R}{100} = 20$$1003100R​−1002900R​=20

$$\dfrac{3100R - 2900R}{100} = 20$$1003100R−2900R​=20

$$\dfrac{200R}{100} = 20$$100200R​=20

$$2R = 20$$2R=20

$$R = 10$$R=10

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Therefore, the rate of interest is 10%.